Base | Representation |
---|---|
bin | 1011111011010011010100… |
… | …0111110110101110011101 |
3 | 1201102122001020021222110122 |
4 | 2332310311013312232131 |
5 | 3204322244130000201 |
6 | 43520120330044325 |
7 | 2522261634216524 |
oct | 276646507665635 |
9 | 51378036258418 |
10 | 13113426406301 |
11 | 41a6411381651 |
12 | 1579577b796a5 |
13 | 74178acc5470 |
14 | 33499c2cb4bb |
15 | 17b19c4a0e1b |
hex | bed351f6b9d |
13113426406301 has 16 divisors (see below), whose sum is σ = 14756942766720. Its totient is φ = 11562079129920.
The previous prime is 13113426406183. The next prime is 13113426406319. The reversal of 13113426406301 is 10360462431131.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 13113426406301 - 222 = 13113422211997 is a prime.
It is a super-2 number, since 2×131134264063012 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13113426406321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30717215 + ... + 31141196.
It is an arithmetic number, because the mean of its divisors is an integer number (922308922920).
Almost surely, 213113426406301 is an apocalyptic number.
It is an amenable number.
13113426406301 is a deficient number, since it is larger than the sum of its proper divisors (1643516360419).
13113426406301 is a wasteful number, since it uses less digits than its factorization.
13113426406301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61859156.
The product of its (nonzero) digits is 31104, while the sum is 35.
Adding to 13113426406301 its reverse (10360462431131), we get a palindrome (23473888837432).
The spelling of 13113426406301 in words is "thirteen trillion, one hundred thirteen billion, four hundred twenty-six million, four hundred six thousand, three hundred one".
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