13113426406300 has 144 divisors (see below), whose sum is σ = 33757475195808. Its totient is φ = 4366719590400.

The previous prime is 13113426406183. The next prime is 13113426406319. The reversal of 13113426406300 is 360462431131.

It is a super-2 number, since 2×13113426406300² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (34).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8784489 + ... + 10168288.

It is an arithmetic number, because the mean of its divisors is an integer number (234426911082).

Almost surely, 2^{13113426406300} is an apocalyptic number.

13113426406300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13113426406300 is an abundant number, since it is smaller than the sum of its proper divisors (20644048789508).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113426406300 is a wasteful number, since it uses less digits than its factorization.

13113426406300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18952856 (or 18952849 counting only the distinct ones).

The product of its (nonzero) digits is 31104, while the sum is 34.

Adding to 13113426406300 its reverse (360462431131), we get a palindrome (13473888837431).

The spelling of 13113426406300 in words is "thirteen trillion, one hundred thirteen billion, four hundred twenty-six million, four hundred six thousand, three hundred".