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131134313494813 is a prime number
BaseRepresentation
bin11101110100010000010110…
…001011000111100100011101
3122012022022120202222012100211
4131310100112023013210131
5114142001033223313223
61142522134424452421
736423066351264466
oct3564202613074435
9565268522865324
10131134313494813
11388688283377a2
121285a86031a111
135822bb328b235
142454d1290bd6d
1510261876c0d0d
hex7744162c791d

131134313494813 has 2 divisors, whose sum is σ = 131134313494814. Its totient is φ = 131134313494812.

The previous prime is 131134313494703. The next prime is 131134313494837. The reversal of 131134313494813 is 318494313431131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88912037945124 + 42222275549689 = 9429318^2 + 6497867^2 .

It is a cyclic number.

It is not a de Polignac number, because 131134313494813 - 237 = 130996874541341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131134313494013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65567156747406 + 65567156747407.

It is an arithmetic number, because the mean of its divisors is an integer number (65567156747407).

Almost surely, 2131134313494813 is an apocalyptic number.

It is an amenable number.

131134313494813 is a deficient number, since it is larger than the sum of its proper divisors (1).

131134313494813 is an equidigital number, since it uses as much as digits as its factorization.

131134313494813 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1119744, while the sum is 49.

The spelling of 131134313494813 in words is "one hundred thirty-one trillion, one hundred thirty-four billion, three hundred thirteen million, four hundred ninety-four thousand, eight hundred thirteen".