Base | Representation |
---|---|
bin | 10011000101010010001… |
… | …001011001110110111001 |
3 | 11122100210202121211210221 |
4 | 103011102021121312321 |
5 | 132441112331102301 |
6 | 2442231152140041 |
7 | 163512210322135 |
oct | 23052211316671 |
9 | 4570722554727 |
10 | 1311343222201 |
11 | 4661570759a1 |
12 | 192192237621 |
13 | 96875173c3c |
14 | 4767dc803c5 |
15 | 2419ebaeda1 |
hex | 13152259db9 |
1311343222201 has 2 divisors, whose sum is σ = 1311343222202. Its totient is φ = 1311343222200.
The previous prime is 1311343222193. The next prime is 1311343222237. The reversal of 1311343222201 is 1022223431131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1044281653801 + 267061568400 = 1021901^2 + 516780^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311343222201 - 23 = 1311343222193 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311343222291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655671611100 + 655671611101.
It is an arithmetic number, because the mean of its divisors is an integer number (655671611101).
Almost surely, 21311343222201 is an apocalyptic number.
It is an amenable number.
1311343222201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311343222201 is an equidigital number, since it uses as much as digits as its factorization.
1311343222201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1311343222201 its reverse (1022223431131), we get a palindrome (2333566653332).
The spelling of 1311343222201 in words is "one trillion, three hundred eleven billion, three hundred forty-three million, two hundred twenty-two thousand, two hundred one".
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