Base | Representation |
---|---|
bin | 1011111011010011101111… |
… | …1101000000010100100010 |
3 | 1201102122100012221001221102 |
4 | 2332310323331000110202 |
5 | 3204323012444040110 |
6 | 43520135542154402 |
7 | 2522264525243363 |
oct | 276647375002442 |
9 | 51378305831842 |
10 | 13113541002530 |
11 | 41a6470032481 |
12 | 15795aa422a02 |
13 | 7417a8979897 |
14 | 3349ad5dbb6a |
15 | 17b1a758a5a5 |
hex | bed3bf40522 |
13113541002530 has 32 divisors (see below), whose sum is σ = 23891574369600. Its totient is φ = 5181608924352.
The previous prime is 13113541002509. The next prime is 13113541002547. The reversal of 13113541002530 is 3520014531131.
It is a junction number, because it is equal to n+sod(n) for n = 13113541002493 and 13113541002502.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6162236 + ... + 8012504.
It is an arithmetic number, because the mean of its divisors is an integer number (746611699050).
Almost surely, 213113541002530 is an apocalyptic number.
13113541002530 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13113541002530 is a deficient number, since it is larger than the sum of its proper divisors (10778033367070).
13113541002530 is a wasteful number, since it uses less digits than its factorization.
13113541002530 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1858898.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 13113541002530 its reverse (3520014531131), we get a palindrome (16633555533661).
The spelling of 13113541002530 in words is "thirteen trillion, one hundred thirteen billion, five hundred forty-one million, two thousand, five hundred thirty".
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