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1311355520023 is a prime number
BaseRepresentation
bin10011000101010010111…
…000010100010000010111
311122100211121202122020211
4103011102320110100113
5132441124003120043
62442232311510251
7163512420001633
oct23052270242027
94570747678224
101311355520023
1146616300548a
12192196388387
139687788b663
1447681761dc3
15241a0cdda9d
hex13152e14417

1311355520023 has 2 divisors, whose sum is σ = 1311355520024. Its totient is φ = 1311355520022.

The previous prime is 1311355519961. The next prime is 1311355520029. The reversal of 1311355520023 is 3200255531131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311355520023 - 217 = 1311355388951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311355520029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655677760011 + 655677760012.

It is an arithmetic number, because the mean of its divisors is an integer number (655677760012).

Almost surely, 21311355520023 is an apocalyptic number.

1311355520023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311355520023 is an equidigital number, since it uses as much as digits as its factorization.

1311355520023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 31.

The spelling of 1311355520023 in words is "one trillion, three hundred eleven billion, three hundred fifty-five million, five hundred twenty thousand, twenty-three".