Base | Representation |
---|---|
bin | 10011000101010010111… |
… | …000010100010000010111 |
3 | 11122100211121202122020211 |
4 | 103011102320110100113 |
5 | 132441124003120043 |
6 | 2442232311510251 |
7 | 163512420001633 |
oct | 23052270242027 |
9 | 4570747678224 |
10 | 1311355520023 |
11 | 46616300548a |
12 | 192196388387 |
13 | 9687788b663 |
14 | 47681761dc3 |
15 | 241a0cdda9d |
hex | 13152e14417 |
1311355520023 has 2 divisors, whose sum is σ = 1311355520024. Its totient is φ = 1311355520022.
The previous prime is 1311355519961. The next prime is 1311355520029. The reversal of 1311355520023 is 3200255531131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311355520023 - 217 = 1311355388951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311355520029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655677760011 + 655677760012.
It is an arithmetic number, because the mean of its divisors is an integer number (655677760012).
Almost surely, 21311355520023 is an apocalyptic number.
1311355520023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311355520023 is an equidigital number, since it uses as much as digits as its factorization.
1311355520023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 1311355520023 in words is "one trillion, three hundred eleven billion, three hundred fifty-five million, five hundred twenty thousand, twenty-three".
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