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1311396921089 is a prime number
BaseRepresentation
bin10011000101010101010…
…110001111111100000001
311122100221111200000211122
4103011111112033330001
5132441220102433324
62442240351122025
7163513431623513
oct23052526177401
94570844600748
101311396921089
11466184412742
121921a8213315
1396883325b28
144768705bbb3
15241a476aa5e
hex1315558ff01

1311396921089 has 2 divisors, whose sum is σ = 1311396921090. Its totient is φ = 1311396921088.

The previous prime is 1311396921083. The next prime is 1311396921101. The reversal of 1311396921089 is 9801296931131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 688181407489 + 623215513600 = 829567^2 + 789440^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311396921089 - 212 = 1311396916993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1311396921089.

It is not a weakly prime, because it can be changed into another prime (1311396921083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655698460544 + 655698460545.

It is an arithmetic number, because the mean of its divisors is an integer number (655698460545).

Almost surely, 21311396921089 is an apocalyptic number.

It is an amenable number.

1311396921089 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311396921089 is an equidigital number, since it uses as much as digits as its factorization.

1311396921089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 629856, while the sum is 53.

The spelling of 1311396921089 in words is "one trillion, three hundred eleven billion, three hundred ninety-six million, nine hundred twenty-one thousand, eighty-nine".