1311402513540 has 48 divisors (see below), whose sum is σ = 4196488044672. Its totient is φ = 299749145856.

The previous prime is 1311402513517. The next prime is 1311402513571. The reversal of 1311402513540 is 453152041131.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 1311402513498 and 1311402513507.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1561193049 + ... + 1561193888.

It is an arithmetic number, because the mean of its divisors is an integer number (87426834264).

Almost surely, 2^{1311402513540} is an apocalyptic number.

1311402513540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1311402513540 is an abundant number, since it is smaller than the sum of its proper divisors (2885085531132).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311402513540 is a wasteful number, since it uses less digits than its factorization.

1311402513540 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3122386956 (or 3122386954 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 1311402513540 its reverse (453152041131), we get a palindrome (1764554554671).

The spelling of 1311402513540 in words is "one trillion, three hundred eleven billion, four hundred two million, five hundred thirteen thousand, five hundred forty".