13114041140311 has 4 divisors (see below), whose sum is σ = 13114052059624. Its totient is φ = 13114030221000.

The previous prime is 13114041140309. The next prime is 13114041140323. The reversal of 13114041140311 is 11304114041131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13114041140311 - 2¹ = 13114041140309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114041140911) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3398880 + ... + 6146581.

It is an arithmetic number, because the mean of its divisors is an integer number (3278513014906).

Almost surely, 2^{13114041140311} is an apocalyptic number.

13114041140311 is a deficient number, since it is larger than the sum of its proper divisors (10919313).

13114041140311 is an equidigital number, since it uses as much as digits as its factorization.

13114041140311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10919312.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 13114041140311 its reverse (11304114041131), we get a palindrome (24418155181442).

The spelling of 13114041140311 in words is "thirteen trillion, one hundred fourteen billion, forty-one million, one hundred forty thousand, three hundred eleven".