131141100000103 has 2 divisors, whose sum is σ = 131141100000104. Its totient is φ = 131141100000102.

The previous prime is 131141100000077. The next prime is 131141100000161. The reversal of 131141100000103 is 301000001141131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131141100000103 - 2²¹ = 131141097902951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131141100000403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570550000051 + 65570550000052.

It is an arithmetic number, because the mean of its divisors is an integer number (65570550000052).

Almost surely, 2^{131141100000103} is an apocalyptic number.

131141100000103 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141100000103 is an equidigital number, since it uses as much as digits as its factorization.

131141100000103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 131141100000103 its reverse (301000001141131), we get a palindrome (432141101141234).

The spelling of 131141100000103 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred million, one hundred three", and thus it is an aban number.