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131141100013020 = 2233519102112518887
BaseRepresentation
bin11101110100010110101010…
…101011101000010111011100
3122012022222002202000001012000
4131310112222223220113130
5114142103433100404040
61142525220055242300
736423426465606036
oct3564265253502734
9565288082001160
10131141100013020
11388706a0130329
1212860035079390
135823725299596
142455397d76c56
1510264333bb130
hex7745aaae85dc

131141100013020 has 192 divisors, whose sum is σ = 429888598809600. Its totient is φ = 33097931562240.

The previous prime is 131141100013009. The next prime is 131141100013127. The reversal of 131141100013020 is 20310001141131.

It is a happy number.

131141100013020 is a `hidden beast` number, since 1 + 311 + 41 + 10 + 0 + 0 + 1 + 302 + 0 = 666.

It is a super-2 number, since 2×1311411000130202 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 131141100012984 and 131141100013002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4216017 + ... + 16734903.

It is an arithmetic number, because the mean of its divisors is an integer number (2239003118800).

Almost surely, 2131141100013020 is an apocalyptic number.

131141100013020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131141100013020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (214944299404800).

131141100013020 is an abundant number, since it is smaller than the sum of its proper divisors (298747498796580).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141100013020 is a wasteful number, since it uses less digits than its factorization.

131141100013020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12519945 (or 12519937 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 131141100013020 its reverse (20310001141131), we get a palindrome (151451101154151).

The spelling of 131141100013020 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred million, thirteen thousand, twenty".