Base | Representation |
---|---|
bin | 11101110100010110101010… |
… | …101011110000000011010101 |
3 | 122012022222002202001122100222 |
4 | 131310112222223300003111 |
5 | 114142103433102411001 |
6 | 1142525220100044125 |
7 | 36423426466066601 |
oct | 3564265253600325 |
9 | 565288082048328 |
10 | 131141100044501 |
11 | 388706a0151a48 |
12 | 12860035093645 |
13 | 58237252aaa01 |
14 | 2455397d84501 |
15 | 10264333c561b |
hex | 7745aaaf00d5 |
131141100044501 has 2 divisors, whose sum is σ = 131141100044502. Its totient is φ = 131141100044500.
The previous prime is 131141100044417. The next prime is 131141100044621. The reversal of 131141100044501 is 105440001141131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130686028376401 + 455071668100 = 11431799^2 + 674590^2 .
It is a cyclic number.
It is not a de Polignac number, because 131141100044501 - 222 = 131141095850197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141100043501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570550022250 + 65570550022251.
It is an arithmetic number, because the mean of its divisors is an integer number (65570550022251).
Almost surely, 2131141100044501 is an apocalyptic number.
It is an amenable number.
131141100044501 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141100044501 is an equidigital number, since it uses as much as digits as its factorization.
131141100044501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 26.
Adding to 131141100044501 its reverse (105440001141131), we get a palindrome (236581101185632).
The spelling of 131141100044501 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred million, forty-four thousand, five hundred one".
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