13114110013420 has 96 divisors (see below), whose sum is σ = 29735222723136. Its totient is φ = 4829540889600.

The previous prime is 13114110013357. The next prime is 13114110013421. The reversal of 13114110013420 is 2431001141131.

It is a junction number, because it is equal to n+sod(n) for n = 13114110013391 and 13114110013400.

It is not an unprimeable number, because it can be changed into a prime (13114110013421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 610885527 + ... + 610906993.

It is an arithmetic number, because the mean of its divisors is an integer number (309741903366).

Almost surely, 2^{13114110013420} is an apocalyptic number.

13114110013420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13114110013420, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14867611361568).

13114110013420 is an abundant number, since it is smaller than the sum of its proper divisors (16621112709716).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114110013420 is a wasteful number, since it uses less digits than its factorization.

13114110013420 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27491 (or 27489 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 13114110013420 its reverse (2431001141131), we get a palindrome (15545111154551).

The spelling of 13114110013420 in words is "thirteen trillion, one hundred fourteen billion, one hundred ten million, thirteen thousand, four hundred twenty".