Base | Representation |
---|---|
bin | 10011000101010110001… |
… | …100000000011101000000 |
3 | 11122100222111011222220120 |
4 | 103011112030000131000 |
5 | 132441232204412230 |
6 | 2442242013140240 |
7 | 163513662456213 |
oct | 23052614003500 |
9 | 4570874158816 |
10 | 1311411013440 |
11 | 466191368510 |
12 | 1921b0a8a680 |
13 | 9688621b2b8 |
14 | 47688c8977a |
15 | 241a5b01310 |
hex | 13156300740 |
1311411013440 has 224 divisors, whose sum is σ = 4809442760064. Its totient is φ = 299216732160.
The previous prime is 1311411013417. The next prime is 1311411013447. The reversal of 1311411013440 is 443101141131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a self number, because there is not a number n which added to its sum of digits gives 1311411013440.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311411013447) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3473029 + ... + 3832068.
Almost surely, 21311411013440 is an apocalyptic number.
1311411013440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1311411013440 is an abundant number, since it is smaller than the sum of its proper divisors (3498031746624).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311411013440 is a wasteful number, since it uses less digits than its factorization.
1311411013440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7305145 (or 7305135 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 1311411013440 its reverse (443101141131), we get a palindrome (1754512154571).
The spelling of 1311411013440 in words is "one trillion, three hundred eleven billion, four hundred eleven million, thirteen thousand, four hundred forty".
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