Base | Representation |
---|---|
bin | 10011000101010110001… |
… | …100000100101111011011 |
3 | 11122100222111012220000001 |
4 | 103011112030010233123 |
5 | 132441232210443003 |
6 | 2442242013353431 |
7 | 163513662561343 |
oct | 23052614045733 |
9 | 4570874186001 |
10 | 1311411031003 |
11 | 46619137a727 |
12 | 1921b0a98877 |
13 | 968862262a8 |
14 | 47688c91d23 |
15 | 241a5b0661d |
hex | 13156304bdb |
1311411031003 has 2 divisors, whose sum is σ = 1311411031004. Its totient is φ = 1311411031002.
The previous prime is 1311411030997. The next prime is 1311411031013. The reversal of 1311411031003 is 3001301141131.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (3001301141131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311411031003 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311411031013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655705515501 + 655705515502.
It is an arithmetic number, because the mean of its divisors is an integer number (655705515502).
Almost surely, 21311411031003 is an apocalyptic number.
1311411031003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311411031003 is an equidigital number, since it uses as much as digits as its factorization.
1311411031003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1311411031003 its reverse (3001301141131), we get a palindrome (4312712172134).
The spelling of 1311411031003 in words is "one trillion, three hundred eleven billion, four hundred eleven million, thirty-one thousand, three".
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