Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …010110010110111001011111 |
3 | 122012022222010112002002120122 |
4 | 131310112223112112321133 |
5 | 114142103443432314123 |
6 | 1142525221135305155 |
7 | 36423426663036005 |
oct | 3564265326267137 |
9 | 565288115062518 |
10 | 131141111213663 |
11 | 388706a6490561 |
12 | 1286003897b1bb |
13 | 58237276bb795 |
14 | 2455399650a75 |
15 | 102643437ebc8 |
hex | 7745ab596e5f |
131141111213663 has 2 divisors, whose sum is σ = 131141111213664. Its totient is φ = 131141111213662.
The previous prime is 131141111213621. The next prime is 131141111213681. The reversal of 131141111213663 is 366312111141131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131141111213663 - 228 = 131140842778207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141111213603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570555606831 + 65570555606832.
It is an arithmetic number, because the mean of its divisors is an integer number (65570555606832).
Almost surely, 2131141111213663 is an apocalyptic number.
131141111213663 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141111213663 is an equidigital number, since it uses as much as digits as its factorization.
131141111213663 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7776, while the sum is 35.
Adding to 131141111213663 its reverse (366312111141131), we get a palindrome (497453222354794).
The spelling of 131141111213663 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, two hundred thirteen thousand, six hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •