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131141111220310 = 2513114111122031
BaseRepresentation
bin11101110100010110101011…
…010110011000100001010110
3122012022222010112002102200211
4131310112223112120201112
5114142103443433022220
61142525221135400034
736423426663064252
oct3564265326304126
9565288115072624
10131141111220310
11388706a6495554
121286003898301a
1358237276c1809
142455399653262
151026434381b5a
hex7745ab598856

131141111220310 has 8 divisors (see below), whose sum is σ = 236054000196576. Its totient is φ = 52456444488120.

The previous prime is 131141111220209. The next prime is 131141111220367. The reversal of 131141111220310 is 13022111141131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1311411112203102 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6557055561006 + ... + 6557055561025.

It is an arithmetic number, because the mean of its divisors is an integer number (29506750024572).

Almost surely, 2131141111220310 is an apocalyptic number.

131141111220310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131141111220310 is a deficient number, since it is larger than the sum of its proper divisors (104912888976266).

131141111220310 is a wasteful number, since it uses less digits than its factorization.

131141111220310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13114111122038.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 131141111220310 its reverse (13022111141131), we get a palindrome (144163222361441).

The spelling of 131141111220310 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, two hundred twenty thousand, three hundred ten".

Divisors: 1 2 5 10 13114111122031 26228222244062 65570555610155 131141111220310