Base | Representation |
---|---|
bin | 1011111011010101111010… |
… | …0010010101010001001000 |
3 | 1201102200211122200211002002 |
4 | 2332311132202111101020 |
5 | 3204330210012304000 |
6 | 43520313310130132 |
7 | 2522315102041163 |
oct | 276653642252110 |
9 | 51380748624062 |
10 | 13114121213000 |
11 | 41a67385a4165 |
12 | 15797307b0948 |
13 | 74186bc36aa2 |
14 | 334a266b2ada |
15 | 17b1dd4998d5 |
hex | bed5e895448 |
13114121213000 has 128 divisors (see below), whose sum is σ = 30978660211200. Its totient is φ = 5196027904000.
The previous prime is 13114121212981. The next prime is 13114121213047. The reversal of 13114121213000 is 31212141131.
13114121213000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 45860465 + ... + 46145535.
It is an arithmetic number, because the mean of its divisors is an integer number (242020782900).
Almost surely, 213114121213000 is an apocalyptic number.
13114121213000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13114121213000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15489330105600).
13114121213000 is an abundant number, since it is smaller than the sum of its proper divisors (17864538998200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13114121213000 is a wasteful number, since it uses less digits than its factorization.
13114121213000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 285528 (or 285514 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 13114121213000 its reverse (31212141131), we get a palindrome (13145333354131).
The spelling of 13114121213000 in words is "thirteen trillion, one hundred fourteen billion, one hundred twenty-one million, two hundred thirteen thousand".
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