Base | Representation |
---|---|
bin | 1011111011010101111010… |
… | …0110111010100110001111 |
3 | 1201102200211201221212012022 |
4 | 2332311132212322212033 |
5 | 3204330210314230404 |
6 | 43520313352000355 |
7 | 2522315115204062 |
oct | 276653646724617 |
9 | 51380751855168 |
10 | 13114122414479 |
11 | 41a6739244919 |
12 | 15797310900bb |
13 | 74186c267918 |
14 | 334a269068d9 |
15 | 17b1dd6358be |
hex | bed5e9ba98f |
13114122414479 has 2 divisors, whose sum is σ = 13114122414480. Its totient is φ = 13114122414478.
The previous prime is 13114122414413. The next prime is 13114122414559. The reversal of 13114122414479 is 97441422141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13114122414479 - 224 = 13114105637263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13114122410479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557061207239 + 6557061207240.
It is an arithmetic number, because the mean of its divisors is an integer number (6557061207240).
Almost surely, 213114122414479 is an apocalyptic number.
13114122414479 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114122414479 is an equidigital number, since it uses as much as digits as its factorization.
13114122414479 is an evil number, because the sum of its binary digits is even.
The product of its digits is 193536, while the sum is 44.
The spelling of 13114122414479 in words is "thirteen trillion, one hundred fourteen billion, one hundred twenty-two million, four hundred fourteen thousand, four hundred seventy-nine".
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