Base | Representation |
---|---|
bin | 10011000101010110010… |
… | …010001001100001100001 |
3 | 11122100222121012210102211 |
4 | 103011112102021201201 |
5 | 132441233112422312 |
6 | 2442242111442121 |
7 | 163514012243146 |
oct | 23052622114141 |
9 | 4570877183384 |
10 | 1311412623457 |
11 | 466192268102 |
12 | 1921b1526341 |
13 | 96886663081 |
14 | 476891883cd |
15 | 241a5d1d3a7 |
hex | 13156489861 |
1311412623457 has 2 divisors, whose sum is σ = 1311412623458. Its totient is φ = 1311412623456.
The previous prime is 1311412623431. The next prime is 1311412623487. The reversal of 1311412623457 is 7543262141131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 675304289361 + 636108334096 = 821769^2 + 797564^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311412623457 - 215 = 1311412590689 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311412623407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655706311728 + 655706311729.
It is an arithmetic number, because the mean of its divisors is an integer number (655706311729).
Almost surely, 21311412623457 is an apocalyptic number.
It is an amenable number.
1311412623457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311412623457 is an equidigital number, since it uses as much as digits as its factorization.
1311412623457 is an evil number, because the sum of its binary digits is even.
The product of its digits is 120960, while the sum is 40.
Adding to 1311412623457 its reverse (7543262141131), we get a palindrome (8854674764588).
The spelling of 1311412623457 in words is "one trillion, three hundred eleven billion, four hundred twelve million, six hundred twenty-three thousand, four hundred fifty-seven".
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