Base | Representation |
---|---|
bin | 10011000101010110010… |
… | …010001001100000101111 |
3 | 11122100222121012210100222 |
4 | 103011112102021200233 |
5 | 132441233112422112 |
6 | 2442242111441555 |
7 | 163514012243045 |
oct | 23052622114057 |
9 | 4570877183328 |
10 | 1311412623407 |
11 | 466192268067 |
12 | 1921b15262bb |
13 | 96886663043 |
14 | 47689188395 |
15 | 241a5d1d372 |
hex | 1315648982f |
1311412623407 has 2 divisors, whose sum is σ = 1311412623408. Its totient is φ = 1311412623406.
The previous prime is 1311412623383. The next prime is 1311412623431. The reversal of 1311412623407 is 7043262141131.
It is a balanced prime because it is at equal distance from previous prime (1311412623383) and next prime (1311412623431).
It is a cyclic number.
It is not a de Polignac number, because 1311412623407 - 224 = 1311395846191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311412623457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655706311703 + 655706311704.
It is an arithmetic number, because the mean of its divisors is an integer number (655706311704).
Almost surely, 21311412623407 is an apocalyptic number.
1311412623407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311412623407 is an equidigital number, since it uses as much as digits as its factorization.
1311412623407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 1311412623407 its reverse (7043262141131), we get a palindrome (8354674764538).
The spelling of 1311412623407 in words is "one trillion, three hundred eleven billion, four hundred twelve million, six hundred twenty-three thousand, four hundred seven".
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