131141323444433 has 2 divisors, whose sum is σ = 131141323444434. Its totient is φ = 131141323444432.

The previous prime is 131141323444343. The next prime is 131141323444447. The reversal of 131141323444433 is 334444323141131.

It is a happy number.

Together with previous prime (131141323444343) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109236611463424 + 21904711981009 = 10451632^2 + 4680247^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131141323444433 is a prime.

It is not a weakly prime, because it can be changed into another prime (131141323444463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570661722216 + 65570661722217.

It is an arithmetic number, because the mean of its divisors is an integer number (65570661722217).

Almost surely, 2^{131141323444433} is an apocalyptic number.

It is an amenable number.

131141323444433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141323444433 is an equidigital number, since it uses as much as digits as its factorization.

131141323444433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 497664, while the sum is 41.

Adding to 131141323444433 its reverse (334444323141131), we get a palindrome (465585646585564).

The spelling of 131141323444433 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-three million, four hundred forty-four thousand, four hundred thirty-three".