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13114132380253 is a prime number
BaseRepresentation
bin1011111011010101111100…
…1100111011101001011101
31201102200212102201011200001
42332311133030323221131
53204330220342132003
643520314345334301
72522315266001602
oct276653714735135
951380772634601
1013114132380253
1141a67439312a3
121579734497391
13741871346a28
14334a27d7c6a9
1517b1de45361d
hexbed5f33ba5d

13114132380253 has 2 divisors, whose sum is σ = 13114132380254. Its totient is φ = 13114132380252.

The previous prime is 13114132380247. The next prime is 13114132380301. The reversal of 13114132380253 is 35208323141131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9501023311129 + 3613109069124 = 3082373^2 + 1900818^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114132380253 - 241 = 10915109124701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114132380203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066190126 + 6557066190127.

It is an arithmetic number, because the mean of its divisors is an integer number (6557066190127).

Almost surely, 213114132380253 is an apocalyptic number.

It is an amenable number.

13114132380253 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114132380253 is an equidigital number, since it uses as much as digits as its factorization.

13114132380253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 37.

The spelling of 13114132380253 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, three hundred eighty thousand, two hundred fifty-three".