131141324000041 has 2 divisors, whose sum is σ = 131141324000042. Its totient is φ = 131141324000040.

The previous prime is 131141323999883. The next prime is 131141324000069. The reversal of 131141324000041 is 140000423141131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80349190540441 + 50792133459600 = 8963771^2 + 7126860^2 .

It is a cyclic number.

It is not a de Polignac number, because 131141324000041 - 2³¹ = 131139176516393 is a prime.

It is not a weakly prime, because it can be changed into another prime (131141324000081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570662000020 + 65570662000021.

It is an arithmetic number, because the mean of its divisors is an integer number (65570662000021).

Almost surely, 2^{131141324000041} is an apocalyptic number.

It is an amenable number.

131141324000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141324000041 is an equidigital number, since it uses as much as digits as its factorization.

131141324000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131141324000041 its reverse (140000423141131), we get a palindrome (271141747141172).

The spelling of 131141324000041 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, forty-one", and thus it is an aban number.