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131141324013100 = 225216715714998583
BaseRepresentation
bin11101110100010110111000…
…000010000111111000101100
3122012022222200100111102112021
4131310112320002013320230
5114142104412421404400
61142525254220315524
736423435155562352
oct3564267002077054
9565288610442467
10131141324013100
11388707a5615965
12128600980a2ba4
13582375c8078cb
1424553b9a057d2
151026447db671a
hex7745b8087e2c

131141324013100 has 72 divisors (see below), whose sum is σ = 286463010693888. Its totient is φ = 52109217633600.

The previous prime is 131141324013019. The next prime is 131141324013101. The reversal of 131141324013100 is 1310423141131.

It is a super-3 number, since 3×1311413240131003 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (131141324013101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 23736409 + ... + 28734991.

It is an arithmetic number, because the mean of its divisors is an integer number (3978652926304).

Almost surely, 2131141324013100 is an apocalyptic number.

131141324013100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131141324013100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (143231505346944).

131141324013100 is an abundant number, since it is smaller than the sum of its proper divisors (155321686680788).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141324013100 is a wasteful number, since it uses less digits than its factorization.

131141324013100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5000335 (or 5000328 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 131141324013100 its reverse (1310423141131), we get a palindrome (132451747154231).

The spelling of 131141324013100 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, thirteen thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 167 334 668 835 1571 1670 3142 3340 4175 6284 7855 8350 15710 16700 31420 39275 78550 157100 262357 524714 1049428 1311785 2623570 4998583 5247140 6558925 9997166 13117850 19994332 24992915 26235700 49985830 99971660 124964575 249929150 499858300 834763361 1669526722 3339053444 4173816805 7852773893 8347633610 15705547786 16695267220 20869084025 31411095572 39263869465 41738168050 78527738930 83476336100 157055477860 196319347325 392638694650 785277389300 1311413240131 2622826480262 5245652960524 6557066200655 13114132401310 26228264802620 32785331003275 65570662006550 131141324013100