13114132432040 has 32 divisors (see below), whose sum is σ = 29541967056000. Its totient is φ = 5239400691264.

The previous prime is 13114132432019. The next prime is 13114132432069. The reversal of 13114132432040 is 4023423141131.

It is a junction number, because it is equal to n+sod(n) for n = 13114132431994 and 13114132432012.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 195349820 + ... + 195416939.

It is an arithmetic number, because the mean of its divisors is an integer number (923186470500).

Almost surely, 2^{13114132432040} is an apocalyptic number.

13114132432040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13114132432040 is an abundant number, since it is smaller than the sum of its proper divisors (16427834623960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114132432040 is a wasteful number, since it uses less digits than its factorization.

13114132432040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 390767609 (or 390767605 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13114132432040 its reverse (4023423141131), we get a palindrome (17137555573171).

The spelling of 13114132432040 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred thirty-two thousand, forty".