Base | Representation |
---|---|
bin | 11101110100010110111000… |
… | …000011010011100011110111 |
3 | 122012022222200101002011201101 |
4 | 131310112320003103203313 |
5 | 114142104413011314223 |
6 | 1142525254231110531 |
7 | 36423435161323135 |
oct | 3564267003234367 |
9 | 565288611064641 |
10 | 131141324323063 |
11 | 388707a580782a |
12 | 12860098212447 |
13 | 582375c8b5a12 |
14 | 24553b9a86755 |
15 | 1026447e284ad |
hex | 7745b80d38f7 |
131141324323063 has 2 divisors, whose sum is σ = 131141324323064. Its totient is φ = 131141324323062.
The previous prime is 131141324323027. The next prime is 131141324323147. The reversal of 131141324323063 is 360323423141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141324323063 - 221 = 131141322225911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131141324423063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570662161531 + 65570662161532.
It is an arithmetic number, because the mean of its divisors is an integer number (65570662161532).
Almost surely, 2131141324323063 is an apocalyptic number.
131141324323063 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141324323063 is an equidigital number, since it uses as much as digits as its factorization.
131141324323063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 37.
Adding to 131141324323063 its reverse (360323423141131), we get a palindrome (491464747464194).
The spelling of 131141324323063 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, three hundred twenty-three thousand, sixty-three".
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