13114132432367 has 2 divisors, whose sum is σ = 13114132432368. Its totient is φ = 13114132432366.

The previous prime is 13114132432279. The next prime is 13114132432411. The reversal of 13114132432367 is 76323423141131.

It is a strong prime.

It is an emirp because it is prime and its reverse (76323423141131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13114132432367 - 2³² = 13109837465071 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114132438367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066216183 + 6557066216184.

It is an arithmetic number, because the mean of its divisors is an integer number (6557066216184).

Almost surely, 2^{13114132432367} is an apocalyptic number.

13114132432367 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114132432367 is an equidigital number, since it uses as much as digits as its factorization.

13114132432367 is an evil number, because the sum of its binary digits is even.

The product of its digits is 217728, while the sum is 41.

Adding to 13114132432367 its reverse (76323423141131), we get a palindrome (89437555573498).

The spelling of 13114132432367 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-two million, four hundred thirty-two thousand, three hundred sixty-seven".