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131141341616123 is a prime number
BaseRepresentation
bin11101110100010110111001…
…000101010001011111111011
3122012022222201120121202100002
4131310112321011101133323
5114142104431423203443
61142525300045503215
736423435461316206
oct3564267105213773
9565288646552302
10131141341616123
1138870804549313
12128600a1b71b0b
13582376335bcb7
1424553bc0a893d
1510264496e22b8
hex7745b91517fb

131141341616123 has 2 divisors, whose sum is σ = 131141341616124. Its totient is φ = 131141341616122.

The previous prime is 131141341616083. The next prime is 131141341616231. The reversal of 131141341616123 is 321616143141131.

Together with next prime (131141341616231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131141341616123 - 212 = 131141341612027 is a prime.

It is a super-2 number, since 2×1311413416161232 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131141341616023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570670808061 + 65570670808062.

It is an arithmetic number, because the mean of its divisors is an integer number (65570670808062).

Almost surely, 2131141341616123 is an apocalyptic number.

131141341616123 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141341616123 is an equidigital number, since it uses as much as digits as its factorization.

131141341616123 is an evil number, because the sum of its binary digits is even.

The product of its digits is 31104, while the sum is 38.

Adding to 131141341616123 its reverse (321616143141131), we get a palindrome (452757484757254).

The spelling of 131141341616123 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-one million, six hundred sixteen thousand, one hundred twenty-three".