Base | Representation |
---|---|
bin | 11101110100010110111001… |
… | …000111010010011011110011 |
3 | 122012022222201121121120210002 |
4 | 131310112321013102123303 |
5 | 114142104432042103433 |
6 | 1142525300105100215 |
7 | 36423435465646004 |
oct | 3564267107223363 |
9 | 565288647546702 |
10 | 131141342144243 |
11 | 3887080487a082 |
12 | 128600a218766b |
13 | 58237634b54b2 |
14 | 24553bc1a51ab |
15 | 10264497989e8 |
hex | 7745b91d26f3 |
131141342144243 has 2 divisors, whose sum is σ = 131141342144244. Its totient is φ = 131141342144242.
The previous prime is 131141342144221. The next prime is 131141342144269. The reversal of 131141342144243 is 342441243141131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131141342144243 - 210 = 131141342143219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131141342144197 and 131141342144206.
It is not a weakly prime, because it can be changed into another prime (131141342144273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570671072121 + 65570671072122.
It is an arithmetic number, because the mean of its divisors is an integer number (65570671072122).
Almost surely, 2131141342144243 is an apocalyptic number.
131141342144243 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141342144243 is an equidigital number, since it uses as much as digits as its factorization.
131141342144243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 110592, while the sum is 38.
Adding to 131141342144243 its reverse (342441243141131), we get a palindrome (473582585285374).
The spelling of 131141342144243 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-two million, one hundred forty-four thousand, two hundred forty-three".
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