131141402001222 has 16 divisors (see below), whose sum is σ = 262283301419760. Its totient is φ = 43713717764192.

The previous prime is 131141402001217. The next prime is 131141402001241. The reversal of 131141402001222 is 222100204141131.

It is a super-2 number, since 2×131141402001222² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131141402001192 and 131141402001201.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17253597 + ... + 23663672.

It is an arithmetic number, because the mean of its divisors is an integer number (16392706338735).

Almost surely, 2^{131141402001222} is an apocalyptic number.

131141402001222 is an abundant number, since it is smaller than the sum of its proper divisors (131141899418538).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141402001222 is a wasteful number, since it uses less digits than its factorization.

131141402001222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41451447.

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 131141402001222 its reverse (222100204141131), we get a palindrome (353241606142353).

The spelling of 131141402001222 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred two million, one thousand, two hundred twenty-two".