Base | Representation |
---|---|
bin | 11101110100010110111100… |
… | …110001000000001010111101 |
3 | 122012022222212212220021011011 |
4 | 131310112330301000022331 |
5 | 114142110043233124013 |
6 | 1142525310134155221 |
7 | 36423440141500453 |
oct | 3564267461001275 |
9 | 565288785807134 |
10 | 131141403411133 |
11 | 38870836415875 |
12 | 128600ba7b2b11 |
13 | 58237730b6cab |
14 | 24553c63929d3 |
15 | 102644ed4bc3d |
hex | 7745bcc402bd |
131141403411133 has 8 divisors (see below), whose sum is σ = 131867831459000. Its totient is φ = 130414996131840.
The previous prime is 131141403411047. The next prime is 131141403411167. The reversal of 131141403411133 is 331114304141131.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 17187102107289 + 113954301303844 = 4145733^2 + 10674938^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131141403411133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131141403411095 and 131141403411104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131141403411173) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7558141 + ... + 17871997.
It is an arithmetic number, because the mean of its divisors is an integer number (16483478932375).
Almost surely, 2131141403411133 is an apocalyptic number.
It is an amenable number.
131141403411133 is a deficient number, since it is larger than the sum of its proper divisors (726428047867).
131141403411133 is a wasteful number, since it uses less digits than its factorization.
131141403411133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10384287.
The product of its (nonzero) digits is 5184, while the sum is 31.
Adding to 131141403411133 its reverse (331114304141131), we get a palindrome (462255707552264).
The spelling of 131141403411133 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred three million, four hundred eleven thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •