131141403411167 has 2 divisors, whose sum is σ = 131141403411168. Its totient is φ = 131141403411166.

The previous prime is 131141403411047. The next prime is 131141403411173. The reversal of 131141403411167 is 761114304141131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131141403411167 - 2⁸ = 131141403410911 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131141403411167.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131141403611167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570701705583 + 65570701705584.

It is an arithmetic number, because the mean of its divisors is an integer number (65570701705584).

Almost surely, 2^{131141403411167} is an apocalyptic number.

131141403411167 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141403411167 is an equidigital number, since it uses as much as digits as its factorization.

131141403411167 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 38.

Adding to 131141403411167 its reverse (761114304141131), we get a palindrome (892255707552298).

The spelling of 131141403411167 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred three million, four hundred eleven thousand, one hundred sixty-seven".