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13114143257 is a prime number
BaseRepresentation
bin11000011011010100…
…11111001000011001
31020211221120111120112
430031222133020121
5203324210041012
610005145334105
7642660243545
oct141552371031
936757514515
1013114143257
11561a656a26
12265ba97335
13130cc27ba7
148c599ca25
1551b49c122
hex30da9f219

13114143257 has 2 divisors, whose sum is σ = 13114143258. Its totient is φ = 13114143256.

The previous prime is 13114143239. The next prime is 13114143271. The reversal of 13114143257 is 75234141131.

13114143257 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13106586256 + 7557001 = 114484^2 + 2749^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13114143257 is a prime.

It is not a weakly prime, because it can be changed into another prime (13114143857) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557071628 + 6557071629.

It is an arithmetic number, because the mean of its divisors is an integer number (6557071629).

Almost surely, 213114143257 is an apocalyptic number.

It is an amenable number.

13114143257 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114143257 is an equidigital number, since it uses as much as digits as its factorization.

13114143257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10080, while the sum is 32.

Adding to 13114143257 its sum of digits (32), we get a square (13114143289 = 1145172).

Adding to 13114143257 its reverse (75234141131), we get a palindrome (88348284388).

The spelling of 13114143257 in words is "thirteen billion, one hundred fourteen million, one hundred forty-three thousand, two hundred fifty-seven".