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131142103311450 = 2352711731011539983
BaseRepresentation
bin11101110100010111100110…
…011110111010010001011010
3122012100001200122212212220010
4131310113212132322101122
5114142113011421431300
61142525503415342350
736423463400525250
oct3564274636722132
9565301618785803
10131142103311450
11388710654a7290
12128602750819b6
1358238550bcbaa
1424554513025d0
1510264914eea50
hex7745e67ba45a

131142103311450 has 384 divisors, whose sum is σ = 415109118173184. Its totient is φ = 26610888960000.

The previous prime is 131142103311449. The next prime is 131142103311463. The reversal of 131142103311450 is 54113301241131.

It is a happy number.

It is a super-2 number, since 2×1311421033114502 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 84388159 + ... + 85928141.

It is an arithmetic number, because the mean of its divisors is an integer number (1081013328576).

Almost surely, 2131142103311450 is an apocalyptic number.

131142103311450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 131142103311450, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (207554559086592).

131142103311450 is an abundant number, since it is smaller than the sum of its proper divisors (283967014861734).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131142103311450 is a wasteful number, since it uses less digits than its factorization.

131142103311450 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1540190 (or 1540185 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 30.

Adding to 131142103311450 its reverse (54113301241131), we get a palindrome (185255404552581).

The spelling of 131142103311450 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred three million, three hundred eleven thousand, four hundred fifty".