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131142104133367 is a prime number
BaseRepresentation
bin11101110100010111100110…
…100010000010111011110111
3122012100001200201102122100111
4131310113212202002323313
5114142113012124231432
61142525503445123451
736423463410520435
oct3564274642027367
9565301621378314
10131142104133367
1138871065a08858
12128602753b9587
13582385531a032
142455451477d55
151026491613347
hex7745e6882ef7

131142104133367 has 2 divisors, whose sum is σ = 131142104133368. Its totient is φ = 131142104133366.

The previous prime is 131142104133329. The next prime is 131142104133401. The reversal of 131142104133367 is 763331401241131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131142104133367 - 239 = 130592348319479 is a prime.

It is a super-2 number, since 2×1311421041333672 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131142104133067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571052066683 + 65571052066684.

It is an arithmetic number, because the mean of its divisors is an integer number (65571052066684).

Almost surely, 2131142104133367 is an apocalyptic number.

131142104133367 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142104133367 is an equidigital number, since it uses as much as digits as its factorization.

131142104133367 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108864, while the sum is 40.

Adding to 131142104133367 its reverse (763331401241131), we get a palindrome (894473505374498).

The spelling of 131142104133367 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred four million, one hundred thirty-three thousand, three hundred sixty-seven".