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131142104202341 is a prime number
BaseRepresentation
bin11101110100010111100110…
…100010010011110001100101
3122012100001200201120010222002
4131310113212202103301211
5114142113012133433331
61142525503450415045
736423463411225511
oct3564274642236145
9565301621503862
10131142104202341
1138871065a55661
1212860275431485
13582385534254b
142455451495141
1510264916289cb
hex7745e6893c65

131142104202341 has 2 divisors, whose sum is σ = 131142104202342. Its totient is φ = 131142104202340.

The previous prime is 131142104202259. The next prime is 131142104202349. The reversal of 131142104202341 is 143202401241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105526824390625 + 25615279811716 = 10272625^2 + 5061154^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131142104202341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131142104202349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571052101170 + 65571052101171.

It is an arithmetic number, because the mean of its divisors is an integer number (65571052101171).

Almost surely, 2131142104202341 is an apocalyptic number.

It is an amenable number.

131142104202341 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142104202341 is an equidigital number, since it uses as much as digits as its factorization.

131142104202341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 131142104202341 its reverse (143202401241131), we get a palindrome (274344505443472).

The spelling of 131142104202341 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred four million, two hundred two thousand, three hundred forty-one".