Base | Representation |
---|---|
bin | 11101110100010111100110… |
… | …100010010011110001100101 |
3 | 122012100001200201120010222002 |
4 | 131310113212202103301211 |
5 | 114142113012133433331 |
6 | 1142525503450415045 |
7 | 36423463411225511 |
oct | 3564274642236145 |
9 | 565301621503862 |
10 | 131142104202341 |
11 | 38871065a55661 |
12 | 12860275431485 |
13 | 582385534254b |
14 | 2455451495141 |
15 | 10264916289cb |
hex | 7745e6893c65 |
131142104202341 has 2 divisors, whose sum is σ = 131142104202342. Its totient is φ = 131142104202340.
The previous prime is 131142104202259. The next prime is 131142104202349. The reversal of 131142104202341 is 143202401241131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105526824390625 + 25615279811716 = 10272625^2 + 5061154^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131142104202341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131142104202349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571052101170 + 65571052101171.
It is an arithmetic number, because the mean of its divisors is an integer number (65571052101171).
Almost surely, 2131142104202341 is an apocalyptic number.
It is an amenable number.
131142104202341 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142104202341 is an equidigital number, since it uses as much as digits as its factorization.
131142104202341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 131142104202341 its reverse (143202401241131), we get a palindrome (274344505443472).
The spelling of 131142104202341 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred four million, two hundred two thousand, three hundred forty-one".
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