Base | Representation |
---|---|
bin | 11101110100010111100111… |
… | …001000100100011111110101 |
3 | 122012100001201102102201111101 |
4 | 131310113213020210133311 |
5 | 114142113022220413214 |
6 | 1142525504445410101 |
7 | 36423463562411425 |
oct | 3564274710443765 |
9 | 565301642381441 |
10 | 131142114232309 |
11 | 38871070686294 |
12 | 12860278869931 |
13 | 582385744493b |
14 | 2455452946485 |
15 | 102649245a774 |
hex | 7745e72247f5 |
131142114232309 has 2 divisors, whose sum is σ = 131142114232310. Its totient is φ = 131142114232308.
The previous prime is 131142114232303. The next prime is 131142114232379. The reversal of 131142114232309 is 903232411241131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111002618065284 + 20139496167025 = 10535778^2 + 4487705^2 .
It is a cyclic number.
It is not a de Polignac number, because 131142114232309 - 225 = 131142080677877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131142114232303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571057116154 + 65571057116155.
It is an arithmetic number, because the mean of its divisors is an integer number (65571057116155).
Almost surely, 2131142114232309 is an apocalyptic number.
It is an amenable number.
131142114232309 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142114232309 is an equidigital number, since it uses as much as digits as its factorization.
131142114232309 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 37.
The spelling of 131142114232309 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred fourteen million, two hundred thirty-two thousand, three hundred nine".
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