Base | Representation |
---|---|
bin | 11101110100010111100111… |
… | …001000100100100000001110 |
3 | 122012100001201102102201112022 |
4 | 131310113213020210200032 |
5 | 114142113022220413314 |
6 | 1142525504445410142 |
7 | 36423463562411462 |
oct | 3564274710444016 |
9 | 565301642381468 |
10 | 131142114232334 |
11 | 38871070686307 |
12 | 12860278869952 |
13 | 582385744495a |
14 | 24554529464a2 |
15 | 102649245a78e |
hex | 7745e722480e |
131142114232334 has 4 divisors (see below), whose sum is σ = 196713171348504. Its totient is φ = 65571057116166.
The previous prime is 131142114232309. The next prime is 131142114232379. The reversal of 131142114232334 is 433232411241131.
131142114232334 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 131142114232294 and 131142114232303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785528558082 + ... + 32785528558085.
It is an arithmetic number, because the mean of its divisors is an integer number (49178292837126).
Almost surely, 2131142114232334 is an apocalyptic number.
131142114232334 is a deficient number, since it is larger than the sum of its proper divisors (65571057116170).
131142114232334 is an equidigital number, since it uses as much as digits as its factorization.
131142114232334 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65571057116169.
The product of its digits is 41472, while the sum is 35.
Adding to 131142114232334 its reverse (433232411241131), we get a palindrome (564374525473465).
The spelling of 131142114232334 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred fourteen million, two hundred thirty-two thousand, three hundred thirty-four".
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