131142131211281 has 2 divisors, whose sum is σ = 131142131211282. Its totient is φ = 131142131211280.

The previous prime is 131142131211271. The next prime is 131142131211337. The reversal of 131142131211281 is 182112131241131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121784136292225 + 9357994919056 = 11035585^2 + 3059084^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131142131211281 is a prime.

It is a super-2 number, since 2×131142131211281² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131142131211271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571065605640 + 65571065605641.

It is an arithmetic number, because the mean of its divisors is an integer number (65571065605641).

Almost surely, 2^{131142131211281} is an apocalyptic number.

It is an amenable number.

131142131211281 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142131211281 is an equidigital number, since it uses as much as digits as its factorization.

131142131211281 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304, while the sum is 32.

The spelling of 131142131211281 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred thirty-one million, two hundred eleven thousand, two hundred eighty-one".