1311422500637 has 2 divisors, whose sum is σ = 1311422500638. Its totient is φ = 1311422500636.

The previous prime is 1311422500613. The next prime is 1311422500643. The reversal of 1311422500637 is 7360052241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1308429425956 + 2993074681 = 1143866^2 + 54709^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311422500637 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311422500597 and 1311422500606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311422500607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711250318 + 655711250319.

It is an arithmetic number, because the mean of its divisors is an integer number (655711250319).

Almost surely, 2^{1311422500637} is an apocalyptic number.

It is an amenable number.

1311422500637 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311422500637 is an equidigital number, since it uses as much as digits as its factorization.

1311422500637 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 35.

Adding to 1311422500637 its reverse (7360052241131), we get a palindrome (8671474741768).

The spelling of 1311422500637 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, five hundred thousand, six hundred thirty-seven".