131142333140242 has 4 divisors (see below), whose sum is σ = 196713499710366. Its totient is φ = 65571166570120.

The previous prime is 131142333140239. The next prime is 131142333140261. The reversal of 131142333140242 is 242041333241131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 125513012221081 + 5629320919161 = 11203259^2 + 2372619^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131142333140198 and 131142333140207.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785583285059 + ... + 32785583285062.

Almost surely, 2^{131142333140242} is an apocalyptic number.

131142333140242 is a deficient number, since it is larger than the sum of its proper divisors (65571166570124).

131142333140242 is an equidigital number, since it uses as much as digits as its factorization.

131142333140242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65571166570123.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 131142333140242 its reverse (242041333241131), we get a palindrome (373183666381373).

The spelling of 131142333140242 in words is "one hundred thirty-one trillion, one hundred forty-two billion, three hundred thirty-three million, one hundred forty thousand, two hundred forty-two".