Base | Representation |
---|---|
bin | 10011000101010110111… |
… | …011000111111000011001 |
3 | 11122101000100102111120011 |
4 | 103011112323013320121 |
5 | 132441243340132013 |
6 | 2442243134001521 |
7 | 163514202450424 |
oct | 23052673077031 |
9 | 4571010374504 |
10 | 1311423364633 |
11 | 466198334108 |
12 | 1921b50462a1 |
13 | 968889540b5 |
14 | 4768a7829bb |
15 | 241a6c40c3d |
hex | 13156ec7e19 |
1311423364633 has 2 divisors, whose sum is σ = 1311423364634. Its totient is φ = 1311423364632.
The previous prime is 1311423364607. The next prime is 1311423364661. The reversal of 1311423364633 is 3364633241131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1265868011664 + 45555352969 = 1125108^2 + 213437^2 .
It is an emirp because it is prime and its reverse (3364633241131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311423364633 - 225 = 1311389810201 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311423364733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711682316 + 655711682317.
It is an arithmetic number, because the mean of its divisors is an integer number (655711682317).
Almost surely, 21311423364633 is an apocalyptic number.
It is an amenable number.
1311423364633 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311423364633 is an equidigital number, since it uses as much as digits as its factorization.
1311423364633 is an evil number, because the sum of its binary digits is even.
The product of its digits is 279936, while the sum is 40.
The spelling of 1311423364633 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred sixty-four thousand, six hundred thirty-three".
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