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1311423364633 is a prime number
BaseRepresentation
bin10011000101010110111…
…011000111111000011001
311122101000100102111120011
4103011112323013320121
5132441243340132013
62442243134001521
7163514202450424
oct23052673077031
94571010374504
101311423364633
11466198334108
121921b50462a1
13968889540b5
144768a7829bb
15241a6c40c3d
hex13156ec7e19

1311423364633 has 2 divisors, whose sum is σ = 1311423364634. Its totient is φ = 1311423364632.

The previous prime is 1311423364607. The next prime is 1311423364661. The reversal of 1311423364633 is 3364633241131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1265868011664 + 45555352969 = 1125108^2 + 213437^2 .

It is an emirp because it is prime and its reverse (3364633241131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311423364633 - 225 = 1311389810201 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311423364733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711682316 + 655711682317.

It is an arithmetic number, because the mean of its divisors is an integer number (655711682317).

Almost surely, 21311423364633 is an apocalyptic number.

It is an amenable number.

1311423364633 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311423364633 is an equidigital number, since it uses as much as digits as its factorization.

1311423364633 is an evil number, because the sum of its binary digits is even.

The product of its digits is 279936, while the sum is 40.

The spelling of 1311423364633 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred sixty-four thousand, six hundred thirty-three".