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1311423364661 is a prime number
BaseRepresentation
bin10011000101010110111…
…011000111111000110101
311122101000100102111121012
4103011112323013320311
5132441243340132121
62442243134002005
7163514202450464
oct23052673077065
94571010374535
101311423364661
11466198334133
121921b5046305
1396888954107
144768a7829db
15241a6c40c5b
hex13156ec7e35

1311423364661 has 2 divisors, whose sum is σ = 1311423364662. Its totient is φ = 1311423364660.

The previous prime is 1311423364633. The next prime is 1311423364681. The reversal of 1311423364661 is 1664633241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1311210496561 + 212868100 = 1145081^2 + 14590^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311423364661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311423364681) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711682330 + 655711682331.

It is an arithmetic number, because the mean of its divisors is an integer number (655711682331).

Almost surely, 21311423364661 is an apocalyptic number.

It is an amenable number.

1311423364661 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311423364661 is an equidigital number, since it uses as much as digits as its factorization.

1311423364661 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 186624, while the sum is 41.

The spelling of 1311423364661 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred sixty-four thousand, six hundred sixty-one".