Base | Representation |
---|---|
bin | 11101110100010111110100… |
… | …110110100110100100010111 |
3 | 122012100002022110112121122001 |
4 | 131310113310312212210113 |
5 | 114142114010131400343 |
6 | 1142525543351020131 |
7 | 36423502356005566 |
oct | 3564276466464427 |
9 | 565302273477561 |
10 | 131142344403223 |
11 | 388711795a608a |
12 | 1286032196a647 |
13 | 582389303394a |
14 | 245547533dbdd |
15 | 10264a777444d |
hex | 7745f4da6917 |
131142344403223 has 2 divisors, whose sum is σ = 131142344403224. Its totient is φ = 131142344403222.
The previous prime is 131142344403209. The next prime is 131142344403247. The reversal of 131142344403223 is 322304443241131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131142344403223 - 29 = 131142344402711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131142344103223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571172201611 + 65571172201612.
It is an arithmetic number, because the mean of its divisors is an integer number (65571172201612).
Almost surely, 2131142344403223 is an apocalyptic number.
131142344403223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142344403223 is an equidigital number, since it uses as much as digits as its factorization.
131142344403223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 165888, while the sum is 37.
Adding to 131142344403223 its reverse (322304443241131), we get a palindrome (453446787644354).
The spelling of 131142344403223 in words is "one hundred thirty-one trillion, one hundred forty-two billion, three hundred forty-four million, four hundred three thousand, two hundred twenty-three".
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