Base | Representation |
---|---|
bin | 11101110100010111111000… |
… | …110101000111011000110111 |
3 | 122012100002111010002021220102 |
4 | 131310113320311013120313 |
5 | 114142114124221402411 |
6 | 1142525554133024315 |
7 | 36423504126055625 |
oct | 3564277065073067 |
9 | 565302433067812 |
10 | 131142411122231 |
11 | 38871203226063 |
12 | 1286034018509b |
13 | 58238a3ac3c52 |
14 | 245548014a515 |
15 | 10264ad552d3b |
hex | 7745f8d47637 |
131142411122231 has 2 divisors, whose sum is σ = 131142411122232. Its totient is φ = 131142411122230.
The previous prime is 131142411122089. The next prime is 131142411122237. The reversal of 131142411122231 is 132221114241131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131142411122231 - 210 = 131142411121207 is a prime.
It is a super-2 number, since 2×1311424111222312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131142411122194 and 131142411122203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131142411122237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571205561115 + 65571205561116.
It is an arithmetic number, because the mean of its divisors is an integer number (65571205561116).
Almost surely, 2131142411122231 is an apocalyptic number.
131142411122231 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142411122231 is an equidigital number, since it uses as much as digits as its factorization.
131142411122231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2304, while the sum is 29.
Adding to 131142411122231 its reverse (132221114241131), we get a palindrome (263363525363362).
The spelling of 131142411122231 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred eleven million, one hundred twenty-two thousand, two hundred thirty-one".
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