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131143133799241 is a prime number
BaseRepresentation
bin11101110100011000100011…
…111001111010001101001001
3122012100011100110221002101121
4131310120203321322031021
5114142122114223033431
61142530153550315241
736423531052525654
oct3564304371721511
9565304313832347
10131143133799241
1138871544153a93
12128605021b8b21
13582398a743095
14245550c10889b
151026501c04611
hex774623e7a349

131143133799241 has 2 divisors, whose sum is σ = 131143133799242. Its totient is φ = 131143133799240.

The previous prime is 131143133799143. The next prime is 131143133799257. The reversal of 131143133799241 is 142997331341131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114409143680841 + 16733990118400 = 10696221^2 + 4090720^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131143133799241 is a prime.

It is not a weakly prime, because it can be changed into another prime (131143133799841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571566899620 + 65571566899621.

It is an arithmetic number, because the mean of its divisors is an integer number (65571566899621).

Almost surely, 2131143133799241 is an apocalyptic number.

It is an amenable number.

131143133799241 is a deficient number, since it is larger than the sum of its proper divisors (1).

131143133799241 is an equidigital number, since it uses as much as digits as its factorization.

131143133799241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1469664, while the sum is 52.

The spelling of 131143133799241 in words is "one hundred thirty-one trillion, one hundred forty-three billion, one hundred thirty-three million, seven hundred ninety-nine thousand, two hundred forty-one".