Base | Representation |
---|---|
bin | 11101110100011000100011… |
… | …111001111010001011100111 |
3 | 122012100011100110221002020222 |
4 | 131310120203321322023213 |
5 | 114142122114223033033 |
6 | 1142530153550314555 |
7 | 36423531052525454 |
oct | 3564304371721347 |
9 | 565304313832228 |
10 | 131143133799143 |
11 | 38871544153a04 |
12 | 128605021b8a5b |
13 | 582398a74301b |
14 | 245550c10882b |
15 | 1026501c04598 |
hex | 774623e7a2e7 |
131143133799143 has 2 divisors, whose sum is σ = 131143133799144. Its totient is φ = 131143133799142.
The previous prime is 131143133799011. The next prime is 131143133799241. The reversal of 131143133799143 is 341997331341131.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (341997331341131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131143133799143 - 224 = 131143117021927 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131143133798143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571566899571 + 65571566899572.
It is an arithmetic number, because the mean of its divisors is an integer number (65571566899572).
Almost surely, 2131143133799143 is an apocalyptic number.
131143133799143 is a deficient number, since it is larger than the sum of its proper divisors (1).
131143133799143 is an equidigital number, since it uses as much as digits as its factorization.
131143133799143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2204496, while the sum is 53.
The spelling of 131143133799143 in words is "one hundred thirty-one trillion, one hundred forty-three billion, one hundred thirty-three million, seven hundred ninety-nine thousand, one hundred forty-three".
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