131143212420440 has 256 divisors, whose sum is σ = 324233072640000. Its totient is φ = 47343839495680.

The previous prime is 131143212420413. The next prime is 131143212420469. The reversal of 131143212420440 is 44024212341131.

It is a junction number, because it is equal to n+sod(n) for n = 131143212420397 and 131143212420406.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 86108477519 + ... + 86108479041.

It is an arithmetic number, because the mean of its divisors is an integer number (1266535440000).

Almost surely, 2^{131143212420440} is an apocalyptic number.

131143212420440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131143212420440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (162116536320000).

131143212420440 is an abundant number, since it is smaller than the sum of its proper divisors (193089860219560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131143212420440 is a wasteful number, since it uses less digits than its factorization.

131143212420440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3750 (or 3746 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 131143212420440 its reverse (44024212341131), we get a palindrome (175167424761571).

The spelling of 131143212420440 in words is "one hundred thirty-one trillion, one hundred forty-three billion, two hundred twelve million, four hundred twenty thousand, four hundred forty".