Base | Representation |
---|---|
bin | 10011000101010111011… |
… | …101010000001001110010 |
3 | 11122101000222021001020021 |
4 | 103011113131100021302 |
5 | 132441303132431120 |
6 | 2442244053434054 |
7 | 163514341502344 |
oct | 23052735201162 |
9 | 4571028231207 |
10 | 1311432311410 |
11 | 4661a2394a41 |
12 | 1921b803b92a |
13 | 9688a767450 |
14 | 4768ba31294 |
15 | 241a790baaa |
hex | 13157750272 |
1311432311410 has 48 divisors (see below), whose sum is σ = 2626811871768. Its totient is φ = 468601079040.
The previous prime is 1311432311393. The next prime is 1311432311429. The reversal of 1311432311410 is 141132341131.
It can be written as a sum of positive squares in 4 ways, for example, as 846604252321 + 464828059089 = 920111^2 + 681783^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5123739 + ... + 5373598.
Almost surely, 21311432311410 is an apocalyptic number.
1311432311410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1311432311410 is an abundant number, since it is smaller than the sum of its proper divisors (1315379560358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311432311410 is a wasteful number, since it uses less digits than its factorization.
1311432311410 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10497419 (or 10497388 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 1311432311410 its reverse (141132341131), we get a palindrome (1452564652541).
The spelling of 1311432311410 in words is "one trillion, three hundred eleven billion, four hundred thirty-two million, three hundred eleven thousand, four hundred ten".
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